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LR018368 - Wisserblad LHD en RHD

Oorspronkelijke prijs - Oorspronkelijke prijs €11,90
Oorspronkelijke prijs
€11,90
€11,90 - €11,90
Huidige prijs €11,90
OEM Part
OEM: Made by an Original Equipment Manufacturer. This part is made by an original equipment manufacturer or under their license, ensuring compatibility and quality.
Brand Bosch, Trico OEM
Ruitenwisserblad LHD en RHD
Vehicle Model Land Rover Discovery 3 2005-2009 (L319)
Range Rover 2002-2012 (L322)
Fitment Notes DISCOVERY 3 2005 - 2009 CLASSIC Ruitenwisser (V)9A999999
RANGE ROVER SPORT 2005 - 2009 Ruitenwisser (V)9A999999
Alternative Codes
DKC500150GLR018368DKC500230

On order 5 units · ETA 12-10-2026

Currently out of stock. Order now — we'll ship as soon as it arrives.


When will my order arrive?

We have 5 units on order from our supplier, expected 12-10-2026. Order now to reserve — we'll dispatch as soon as stock arrives.

  • Netherlands / Belgium / Germany: 2–4 working days after dispatch.
  • Other EU countries + UK: 4–8 working days after dispatch.

Need it sooner? Contact us about express import (2–5 business days).

Job kits containing this part

This part is included in 0 job kit(s) below. Pick the kit that matches your vehicle and job, then add what you need.

Frequently asked questions

What is the DKC500150G wiper blade used for?
It's a windscreen wiper blade suitable for both left-hand drive (LHD) and right-hand drive (RHD) applications, referenced under LR018368.
Which vehicles does the DKC500150G fit?
Per SAP fitment data, it's listed for the Discovery 3 (2005-2009) and Range Rover Sport (2005-2009), suitable for both LHD and RHD windscreen wiper systems.
Is there an alternative code for the DKC500150G?
Yes, DKC500230 is listed as an alternative for this same wiper blade.
Why should a worn wiper blade like the DKC500150G be replaced promptly?
A worn or split wiper blade leaves streaks and reduces visibility in wet weather, which is a safety concern. Replace it as soon as it starts juddering or smearing rather than waiting for it to fail completely.